# What is the equation of the line with slope  m= 3/4  that passes through  (-1,5) ?

Jan 20, 2016

4y -3x - 23 = 0

#### Explanation:

y - b = m(x - a ) is one form of the equation of a straight line where m represents the gradient (slope ) and ( a , b ) the coordinates of a point on the line.

In this question $m = \frac{3}{4} \mathmr{and} \left(a , b\right) = \left(- 1 , 5\right)$

(using these values in the equation ):

$y - 5 = \frac{3}{4} \left(x + 1\right)$

( multiply through by 4 to eliminate fraction )

4y - 20 = 3 ( x + 1 ) so 4y - 20 = 3x + 3

hence 4y - 3x - 23 = 0 is the equation of the line.