What is the equation of the line with slope # m= 3/4 # that passes through # (-1,5) #?
4y -3x - 23 = 0
y - b = m(x - a ) is one form of the equation of a straight line where m represents the gradient (slope ) and ( a , b ) the coordinates of a point on the line.
In this question
# m = 3/4 and (a , b ) = ( - 1 , 5 )#
(using these values in the equation ):
# y - 5 = 3/4 (x + 1 ) #
( multiply through by 4 to eliminate fraction )
4y - 20 = 3 ( x + 1 ) so 4y - 20 = 3x + 3
hence 4y - 3x - 23 = 0 is the equation of the line.