# What is the equation of the line with slope  m= -3/5  that passes through  (-2,-3) ?

Jan 12, 2016

If the slope of the line and any one point on the line are given then we find the equation of the line as

$y - {y}_{1} = m \left(x - {x}_{1}\right)$

Where $m$ is the slope and $\left({x}_{1} , {y}_{1}\right)$ are the coordinates of the point.

Here $m = - \frac{3}{5}$ and $\left({x}_{1} , {y}_{1}\right) = \left(- 2 , - 3\right)$.

Therefore, the equation of line is
$y - \left(- 3\right) = - \frac{3}{5} \left\{x - \left(- 2\right)\right\}$

$\implies y + 3 = - \frac{3}{5} \left(x + 2\right)$

$\implies - 5 y - 15 = 3 x + 6$

$\implies 3 x + 5 y + 21 = 0$