# What is the equation of the line with slope  m= 7/4  that passes through  (5,8) ?

Jan 9, 2016

4y - 7x + 3 = 0

#### Explanation:

The standard form of the equation of a straight line is :

y - b = m(x - a ) where m represents the slope and (a , b )
represent the coordinates of a point on the line.

In this case m = $\frac{7}{4}$ and (a , b ) = (5 , 8 )

equation can be written as y - 8 = $\frac{7}{4} \left(x - 5\right)$

at this stage multiply through the equation by 4 to eliminate fractions.

ie. 4y - 32 = 7(x - 5 ) =7x - 35

hence equation of line is 4y - 7x + 3 = 0