What is the equation of the line with slope # m= 7/4 # that passes through # (5,8) #?

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Answer 1 · 2016-01-09T11:21:02

4y - 7x + 3 = 0

The standard form of the equation of a straight line is :

y - b = m(x - a ) where m represents the slope and (a , b )
represent the coordinates of a point on the line.

In this case m = #7/4 # and (a , b ) = (5 , 8 )

equation can be written as y - 8 = #7/4(x - 5 ) #

at this stage multiply through the equation by 4 to eliminate fractions.

ie. 4y - 32 = 7(x - 5 ) =7x - 35

hence equation of line is 4y - 7x + 3 = 0