What is the equation of the line with slope # m= 7/4 # that passes through # (5,8) #?
4y - 7x + 3 = 0
The standard form of the equation of a straight line is :
y - b = m(x - a ) where m represents the slope and (a , b )
represent the coordinates of a point on the line.
In this case m =
equation can be written as y - 8 =
at this stage multiply through the equation by 4 to eliminate fractions.
ie. 4y - 32 = 7(x - 5 ) =7x - 35
hence equation of line is 4y - 7x + 3 = 0