# What is the equation of the normal line of #f(x)=1/sqrt(x^2-2x+1)# at #x=2 #?

##### 1 Answer

Let's start by simplifying the function.

Now, let's start by finding the corresponding y-coordinate to

Next, let's differentiate the function.

By the quotient rule:

The slope of the tangent (the line that touches the graph at the point

The *normal line* is perpendicular to the tangent. So, the slope of the normal line is

We now know the normal line's point of contact on the function

Hence, the equation of the normal line is

Hopefully this helps!