# What is the equation of this circle with the end points of the diameter are at (-4,-1) and (0,-4)?

${\left(x + 2\right)}^{2} + {\left(y + \frac{5}{2}\right)}^{2} = \frac{25}{4}$
So, C is $\left(\frac{- 4 + 0}{2} , \frac{- 1 - 4}{2}\right) = \left(- 2 , - \frac{5}{2}\right)$.
$R a \mathrm{di} u s = \frac{\mathrm{di} a m e t e r}{2} = . \frac{\sqrt{16 + 9}}{2} = \frac{5}{2}$
The equation is ${\left(x + 2\right)}^{2} + {\left(y + \frac{5}{2}\right)}^{2} = \frac{25}{4}$