What is the exact value of #sin 60 - cos 60#? Trigonometry Right Triangles Trigonometric Functions of Any Angle 1 Answer Olivier B. Jun 24, 2015 #sin(60°)-cos(60°)=(sqrt3-1)/2# Explanation: The exact values of #cos(60°)# and #sin(60°)# are: #cos(60°)=cos(pi/3)=1/2# #sin(60°)=sin(pi/3)=sqrt3/2# #rarr sin(60°)-cos(60°)=sqrt3/2-1/2=(sqrt3-1)/2# Answer link Related questions How do you find the trigonometric functions of any angle? What is the reference angle? How do you use the ordered pairs on a unit circle to evaluate a trigonometric function of any angle? What is the reference angle for #140^\circ#? How do you find the value of #cot 300^@#? What is the value of #sin -45^@#? How do you find the trigonometric functions of values that are greater than #360^@#? How do you use the reference angles to find #sin210cos330-tan 135#? How do you know if #sin 30 = sin 150#? How do you show that #(costheta)(sectheta) = 1# if #theta=pi/4#? See all questions in Trigonometric Functions of Any Angle Impact of this question 17983 views around the world You can reuse this answer Creative Commons License