# What is the excluded value for y=1/(x+3)?

$x = - 3$
$\text{the denominator of y cannot be zero as this would make}$
$\text{y undefined. Equating the denominator to zero and}$
$\text{solving gives the value that x cannot be}$
$\text{solve "x+3=0rArrx=-3larrcolor(red)" excluded value}$