What is the expected value of the sum of two rolls of a six sided die?

1 Answer
Apr 30, 2018

77

Explanation:

Intuitively we would expect the sum of a single die to be the average of the possible outcomes, ie:

S= (1+2+3+4+5+6)/6 = 3.5 S=1+2+3+4+5+66=3.5

And so we would predict the sum of a two die to be twice that of one die, ie we would predict the expected value to be 77

If we consider the possible outcomes from the throw of two dice:

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And so if we define XX as a random variable denoting the sum of the two dices, then we get the following distribution:

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So then we compute the expected value, using

E(X) = sum x(P(X)=x) E(X)=x(P(X)=x)

\ \ \ \ \ \ \ \ \ = 2 * 1/36 + 3 * 2/36 + 4 * 3/36 + 5 * 4/36
\ \ \ \ \ \ \ \ \ \ \ \ \ + 6 * 5/36 + 7 * 6/36 + 8 * 5/36 + 9 * 4/36
\ \ \ \ \ \ \ \ \ \ \ \ \ + 10 * 3/36 + 11 * 2/36 + 12 * 1/36

\ \ \ \ \ \ \ \ \ = (2+6+12+20+30+42+40+36+30+22+12)/36

\ \ \ \ \ \ \ \ \ = (252)/36

\ \ \ \ \ \ \ \ \ = 7