What is the factorization of #x^2+5x +4#?

1 Answer
Dec 20, 2016

The set up would be according to #(x + a)(x + b)#

Explanation:

So, you need to look at it in terms of two numbers that add up to #5x# and multiply to #4#.

The two numbers are #1# and #4#.

So, #(x + 1)(x + 4)#.

Check it to make sure it adds up to #x^2 + 5x + 4#

So, multiply using FOIL
(First: The #x# in the left parentheses and the #x# in the right parentheses,
Outer: The #x#in the left parentheses and the #4# in the right parentheses,
Inner: The #1# in the left parentheses and the #x# in the right parentheses,
Last: The #1# in the left parentheses and the #4# in the right parentheses)

So, #x*x = x^2 + 4x + (1)x + (1)(4)# adds up to #x^2 + 5x + 4#.
Yep, the answers checks out.