# What is the final temperature of water if it used 520 J from 52 degrees C?

Mar 27, 2015

The final temperature depends on the mass of the water, and the mass must be sufficient that the water does not boil.

But we can do a general calculation.

q = mcΔT

ΔT = T_2 –T_1 = q/(mc)

${T}_{2} = {T}_{1} + \frac{q}{m c}$

T_2 = "52 °C" + (520 cancel("J"))/(m × 4.184 cancel("J")"g⁻¹°C⁻"¹)
${T}_{2} = \frac{\text{52 °C" + "124 g°C}}{m}$
Now you can insert your own value of $m$ and calculate the value of ${T}_{2}$.