Question

What is the foci of `25x^2+36y^2=900`?

Answer 1

`(-sqrt(11),0) and (sqrt(11),0)`

Explanation:

Standard form is:

`(x - 0)^2/6^2 + (y - 0)^2/5^2 = 1`

The focal distance, c, is computed using

`c^2 = a^2 - b^2`

`c^2 = 36 - 25`

`c^2 = 11`

`c = sqrt(11)`