What is the force, in terms of Coulomb's constant, between two electrical charges of #-6 C# and #-16 C# that are #9 m # apart?

2 Answers
Jun 12, 2018

Answer:

I get approximately #10.7k#.

Explanation:

Coulomb's law states that:

#F=k(q_1q_2)/r^2#

where:

  • #k# is Coulomb's constant

  • #q_1,q_2# are charges of the two charges in coulombs

  • #r# is the distance between the charges in meters

So, we get:

#F=k(-6*-16)/9#

#~~10.7k#

Jun 12, 2018

Answer:

#F~~1.0652*10^10 N#

Explanation:

Coulomb's Law with Coulomb's constant:

#F=(kQ_1Q_2)/r^2#

We will assume that the charges occur in a vacuum.

#k= 8.988*10^9 (Nm^2)/C^2#
#Q_1=-6 C#
#Q_2=-16 C#
#r=9 m#

#F=(( 8.988*10^9)(-6)(-16))/9^2#

#F~~1.0652*10^10 N#