What is the force, in terms of Coulomb's constant, between two electrical charges of #24 C# and #-6 C# that are #12 m # apart?

1 Answer
Dec 30, 2015

Answer:

#F=9*10^9N#

Explanation:

The electrostatic force between two charges is given by
#F=(kq_1q_2)/r^2#
Where #F# is the force between the charges, #k# is the constant and its value is #9*10^9#,#q_1# and #q_2# are the magnitudes of the charges and #r# is the distance between the two charges.

Here #F=??#, #k=9*10^9Nm^2/C^2#, #q_1=24C#, #q_2=-6C# and #r=12m#.

#implies F=(9*10^9*24*6)/12^2=(1296*10^9)/144=9*10^9N#
#implies F=9*10^9N#
Note:- The negative sign of the charges is not taken in the problems.