What is the force, in terms of Coulomb's constant, between two electrical charges of #44 C# and #39 C# that are #12 m # apart?

1 Answer
Nov 29, 2016

Answer:

The force '#F'=11.91k C^2//m^2#.

Explanation:

The coulomb's law gives #F=(k q_1q_2)/r^2#, where 'k' is the proportionality constant. It is also called as coulomb's constant as it as derived from coulomb's law.
Proportionality constant 'k' is equal to '#(1)/(4piepsilon_0)#'
so substituting the given values in above equation of coulomb's law we get,
.#F=(k(44C)(39C))/(12m)^2#
#:.# The force in terms of coulomb's constant 'k' is #11.9 k (C^2//m^2)~~12k(C^2//m^2)#