# What is the force, in terms of Coulomb's constant, between two electrical charges of -45 C and 42 C that are 15 m  apart?

Jul 2, 2016

$F = - 8.4 K$

#### Explanation:

Force experienced between two charged bodies is $F = K \frac{{q}_{1} {q}_{2}}{r} ^ 2$

Taking ${q}_{1} = - 45 C$, ${q}_{2} = 42 C$ and $r = 15 m$
We get
$F = K \frac{- {\cancel{45}}^{1} \cdot 42}{{\cancel{15}}^{1} \cdot {\cancel{15}}^{5}}$

So, the remainder is left to as an exercise to the reader.