What is the force, in terms of Coulomb's constant, between two electrical charges of #-45 C# and #60 C# that are #15 m # apart?

1 Answer

Answer:

Force 'F' in terms of coulomb's constant 'k' is -12k Newtons.

Explanation:

According to the Coulomb's Law
#F = (kq_1q_2)/r^2#.
Here the coulomb's constant 'k' is often written as #1/(4piepsilon_"0")# so that the force equation becomes
#F = [1/(4piepsilon_"0")][(q_1q_2)/r^2]#
In S.I units , the coulomb's constant 'k' is measured to be #8.98755xx10^9 N m^2 C^-2 ~~9xx10^9 Nm^2C^-2#
By substituting the given values in terms of 'k' we get,
Force# F = [k(-45)(60)]/(15)^2=-12k# Newtons.
In terms of numericals #F = -108xx10^9#Newtons.