What is the formula for Hubble's Law?

Jan 5, 2016

$v = H 0 \cdot r$

Explanation:

Hubble's law states that Every object in the observable universe is receding away from us at a speed proportional to it's distance. So, the greater the distance, the faster that object is traveling away from us. This can be given by,

$v = H \circ \cdot r$

Where,

$v$ is the velocity.

$H \circ$ is the Hubble's constant, 70 km ${\sec}^{-} 1$ $m e g a p a r {\sec}^{-} 1$

This means that an object at a distance of 1 Megarparsec will have a speed of about 70 km/ sec.

$r$ is the distance.