# What is the formula weight of silver chromate (Ag_2CrO_4) in amu?

Nov 13, 2016

The formula weight for $\text{Ag"_2"CrO"_4}$ is $\text{331.728 u}$.

#### Explanation:

In order to determine the formula weight of a compound, multiply the atomic weight on the periodic table of each element by its subscript and add the results.

Compound: silver chromate
Formula Unit: $\text{Ag"_2"CrO"_4}$

(2xx"107.868 u Ag")+(1xx"51.9961 u Cr")+(4xx"15.999 u O")="331.728 u"