What is the general equation of a circle which passes through #A#(1,1), #B#(2,-1),and #C#(2,3)?
First plot the points out.
An important concept is that a triangle formed by joining the two ends of a diameter and any other point on the circumference will always be a right angle triangle.
We want to find a diameter on our circle. Therefore we want to construct a right angle triangle with all 3 points on the circumference of the circle.
To do so, we observe that there must be a point,
Try to understand why point
Now we know that
The radius is
The equation of the circle is: