# What is the general form of the equation of a circle with a center at the (10, 5) and a radius of 11?

Jan 2, 2016

${\left(x - 10\right)}^{2} + {\left(y - 5\right)}^{2} = 121$

#### Explanation:

The general form of a circle:

${\left(x - h\right)}^{2} + {\left(y - k\right)}^{2} - {r}^{2}$

Where:

$\left(h , k\right)$ is the center
$r$ is the radius

Thus, we know that

$h = 10 , k = 5$
$r = 11$

So, the equation for the circle is

${\left(x - 10\right)}^{2} + {\left(y - 5\right)}^{2} = {11}^{2}$

Simplified:

${\left(x - 10\right)}^{2} + {\left(y - 5\right)}^{2} = 121$

graph{(x-10)^2+(y-5)^2=121 [-10.95, 40.38, -7.02, 18.63]}