What is the growth factor, initial amount for #M(t)=8(2)^(1/6t)#?

1 Answer
Jun 22, 2018

Answer:

Growth factor = 2
Initial Amount = 8

Explanation:

You're using the form #A(t)=A_0(b)^(t/k)#, where:
#A_0# = the initial amount
#b# = the growth factor
#t# = the amount of time elapsed
#k# = the amount of time it takes to double/triple/etc.

Note: M(t) and A(t) are the same, just using different variables.

Your equation represents a doubling in whatever the problem applies to. It takes 6 years to double. In order to avoid confusion, you can place the #t# in the fraction in the exponent:

#M(t)=8(2)^(t/6)#