What is the H+ concentration (in molarity) of a solution with a pOH of 6.7?

1 Answer
Jun 7, 2016

Answer:

#[H^(+)] = 5.01xx10^(-8) M#

Explanation:

You want to use the following relationship:

#pOH + pH = 14#

Since we are given the pOH, we can determine the pH by subtracting the pOH from 14 like so:

14 - pOH = 7.3.

7.3 represents the pH of the solution and we can obtain the concentration of hydrogen ions in solution by taking the antilog of the pH. The antilog is #10^(-)# raised to some value, which is #10^(-7.3)# in our case.

#10^(-7.3)# = #5.01xx10^(-8) M#

Tips:
#[H^(+)]# = antilog(-pH)
pH = -log#[H^(+)]#

I hope this explanation is understandable!

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