Question

What is the H+ concentration (in molarity) of a solution with a pOH of 6.7?

Answer 1

`[H^(+)] = 5.01xx10^(-8) M`

Explanation:

You want to use the following relationship:

`pOH + pH = 14`

Since we are given the pOH, we can determine the pH by subtracting the pOH from 14 like so:

14 - pOH = 7.3.

7.3 represents the pH of the solution and we can obtain the concentration of hydrogen ions in solution by taking the antilog of the pH. The antilog is `10^(-)` raised to some value, which is `10^(-7.3)` in our case.

`10^(-7.3)` = `5.01xx10^(-8) M`

Tips:
`[H^(+)]` = antilog(-pH)
pH = -log`[H^(+)]`

I hope this explanation is understandable!

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