What is the #[H^+]# of a solution with a pH of 6.6?

1 Answer
anor277
Jun 17, 2016

#[H^+]=10^(-6.6)# #mol*L^-1#

Explanation:

#pH=-log_10[H^+]# by definition.

If #pH=6.6#, then to get #[H^+]# we take the antilogarithm:

#[H^+]# #=# #10^(-6.6)# #mol*L^-1# with respect to #H^+# or #H_3O^+#, an equivalent representation.

This solution is very slightly acidic. I don't think you could taste the difference.

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