What is the heat released when 25.0 grams of water freezes at 0°C?
To calculate the amount of heat entering or leaving a system, the equation
m = mass (in grams)
c = specific heat capacity (J/g°C)
ΔT = change in temperature (°C)
Here, we will use the specific heat capacity for liquid water which is 4.19 J/g°C.
The mass given is 25.0 grams.
As for the change in temperature, I will assume that it start off at room temperature, 25°C.
Take into account significant figures and the answer should be