What is the image of (6, -3) reflected over the line y=4?

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Answer 1 · 2017-02-25T15:21:25

Coordinates of image are $(6, 11)$ $(6,11)$

As $y = 4$ $y=4$ is parallel to $x$ $x$ -axis,

abscissa of image would not change and will be $6$ $6$ .

Further distance of $(6, - 3)$ $(6,-3)$ from $y = 4$ $y=4$ is $| - 3 - 4 | = 7$ $|-3-4|=7$ and point is below line $y = 4$ $y=4$

hence image will be further $7$ $7$ from it and hence

its ordinate would be $4 + 7 = 11$ $4+7=11$ and

Coordinates of image are $(6, 11)$ $(6,11)$
graph{((x-6)^2+(y-11)^2-0.1)((x-6)^2+(y+3)^2-0.1)(y-4)=0 [-16.58, 23.42, -4.96, 15.04]}