Question

What is the implicit derivative of `1= xy-(x^2-y)^2+2y`?

Answer 1

`(dy/dx)=(2x-y)/(x+2y+2)`

Explanation:

`1=xy-(x^2-y^2)+2y`
Rewritten:
`1=xy-x^2+y^2+2y`

`0=x(dy/dx)+y-2x+2y(dy/dx)+2(dy/dx)`
`0=(dy/dx)(x+2y+2)+y-2x`
`(dy/dx)(x+2y+2)=2x-y`

`(dy/dx)=(2x-y)/(x+2y+2)`