Question

What is the instantaneous rate of change of `f(x)=1/(x^2-2x+5 )` at `x=0`?

Answer 1

`2/25`

Explanation:

f(x) =`(x^2-2x+5)^-1`
`d/dxf(x) = (-1)(x^2-2x+5)^-2d/dx(x^2-2x+5)`