Question

What is the integral of `sec^-1(x)`?

Answer 1

We apply the reciprocal properties of trigonometric functions.

By definition,

`sec^-1 x = 1/sec x`

Therefore, the `int sec^-1 x dx` is

`int (1/sec x) dx`

We know that `1/sec x = cos x`

Thus,

`int cos x dx`

`sin x + c`