What is the integral of #sqrt(x)#?

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Answer 1 · 2014-12-11T17:29:49

#int sqrt{x} dx#

by rewriting the square-root as the 1/2-power,

#=int x^{1/2}dx#

by Power Rule,

#={x^{3/2}}/{3/2}+C#

by cleaning up a bit,

#=2/3x^{3/2}+C#

I hope that this was helpful.