What is the inverse of #y = a*ln(bx)# ?

1 Answer
Mar 25, 2016

Answer:

#y=(e^(x/a))/b#

Explanation:

Write as #y/a=ln(bx)#

Another way of writing the same thing is: #e^(y/a)=bx#

#=>x=1/bxx e^(y/a)#

Where the is an #x# write #y# and where original #y# was write #x#

#y=(e^(x/a))/b#

This plot will be a reflection of the original equation about the plot of y=x.

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The formatting has not come out very clearly

Read as #y# equals #e# raised to the power of #x/a# all over #b#