# What is the kinetic energy in kilojoules of a 2360 lb (1070 kg) car moving at 63.3 mi/h (28.3 m/s)?

$428.5 k J$
$K = \frac{1}{2} m {v}^{2} = \frac{1}{2} \cdot 1070 {\left(28.3\right)}^{2} = 428.5 k J$