What is the kinetic energy of a #9 kg# object moving at #5/4 m/s#?

3 Answers
Apr 1, 2018

Answer:

#"7.03 J"#

Explanation:

#"K.E" = 1/2\ "mv"^2 = 1/2 × "9 kg" × (5/4\ "m/s")^2 = 225/32\ "J" = "7.03 J"#

Apr 2, 2018

Answer:

Approximately #7.03# joules.

Explanation:

Kinetic energy is expressed through the equation,

#"KE"=1/2mv^2#

  • #m# is the mass of the object in kilograms

  • #v# is the velocity of the object in meters per second

So, we plug in the values into the given equation, and we get

#"KE"=1/2*9 \ "kg"*(1.25 \ "m/s")^2#

#=4.5 \ "kg"*1.5625 \ "m"^2"/s"^2#

#=7.03125 \ "J"#

#~~7.03 \ "J"#

Apr 2, 2018

Answer:

I retained answer in fractions as the velocity is given in fractions.

Explanation:

Kinetic energy is given by the expression for a body of mass #m# moving with velocity #v#

#KE=1/2mv^2#

Inserting given values we get

#KE=1/2xx9xx(5/4)^2#
#KE=225/32#
#KE=7 1/32\ J#