Question

What is the kinetic energy of a `9 kg` object moving at `5/4 m/s`?

Answer 1

`"7.03 J"`

Explanation:

`"K.E" = 1/2\ "mv"^2 = 1/2 × "9 kg" × (5/4\ "m/s")^2 = 225/32\ "J" = "7.03 J"`

Answer 2

Approximately `7.03` joules.

Explanation:

Kinetic energy is expressed through the equation,

`"KE"=1/2mv^2`

• `m` is the mass of the object in kilograms

• `v` is the velocity of the object in meters per second

So, we plug in the values into the given equation, and we get

`"KE"=1/2*9 \ "kg"*(1.25 \ "m/s")^2`

`=4.5 \ "kg"*1.5625 \ "m"^2"/s"^2`

`=7.03125 \ "J"`

`~~7.03 \ "J"`

Answer 3

I retained answer in fractions as the velocity is given in fractions.

Explanation:

Kinetic energy is given by the expression for a body of mass `m` moving with velocity `v`

`KE=1/2mv^2`

Inserting given values we get

`KE=1/2xx9xx(5/4)^2`
`KE=225/32`
`KE=7 1/32\ J`