What is the LCD of 15x^2 and 6x^5?

Nov 16, 2016

$L C M = 30 {x}^{5}$

Explanation:

The LCD must contain the whole of $15 {x}^{2} \mathmr{and} 6 {x}^{5}$, but without any duplicates (which are given by the HCF)

Use the product of prime factors:

$15 {x}^{2} = \text{ } 3 \times 5 \times x \times x$
$6 {x}^{5} = 2 \times 3 \text{ } \times x \times x \times x \times x \times x$

$L C M = 2 \times 3 \times 5 \times x \times x \times x \times x \times x$

$L C M = 30 {x}^{5}$