# What is the length of the major axis of the conic section (x+2)^2/49 + (y-1)^2/25 =1?

Jul 27, 2018

$14$.

#### Explanation:

If the eqn. of an ellipse is ${x}^{2} / {a}^{2} + {y}^{2} / {b}^{2} = 1 , a > b ,$

the length of its major axis is $2 a$.

In our case, ${a}^{2} = 49 , {b}^{2} = 25. \therefore a = 7 , b = 5 , \mathmr{and} , a > b .$

Hence, the required length is $2 \times 7 = 14$.