# What is the Lewis dot structure of Na_4Si?

Nov 20, 2016

look on the periodic table of the elements Na and Si!

$N {a}^{11}$ = $1 {s}^{2} 2 {s}^{2} 2 {p}^{6} 3 {s}^{1}$ and

$S {i}^{14}$ = $1 {s}^{2} 2 {s}^{2} 2 {p}^{6} 3 {s}^{2} 3 {p}^{2}$

#### Explanation:

$N {a}^{11}$ = $1 {s}^{2} 2 {s}^{2} 2 {p}^{6} 3 {s}^{1}$ and

$S {i}^{14}$ = $1 {s}^{2} 2 {s}^{2} 2 {p}^{6} 3 {s}^{2} 3 {p}^{2}$ $\implies$ Excited state $\implies$ $1 {s}^{2} 2 {s}^{2} 2 {p}^{6} 3 {s}^{1} {p}^{3}$

Silicon is in the same carbon family, so remember the organic chemistry of carbon, it has sp3 hybridization and makes 4 bonds.

The Lewis dot structure of $N {a}^{4} S i$ is tetrahedral structure!

With sigma bonds ($s - s {p}^{3}$)