What is the lewis dot structure of Na2SO4?

1 Answer
Jun 28, 2017

Answer:

We will confine the answer to #"sulfate ion......."#

Explanation:

For #SO_4^(2-)#, a reasonable Lewis structure to accommodate the 32 electrons is.....#(O=)_2S(-O^(-))_2#, and clearly this is a derivative of the parent #"sulfuric acid"#, .....#(O=)_2S(-OH)_2#. Given this Lewis structure, there are 6 valence electrons associated with the doubly bound oxygens (and hence these are neutral), 6 valence electrons with the central sulfur (and hence a neutral sulfur), and 7 valence electrons associated with each singly bound oxygen atoms, and hence these centres bear the 2 required formal NEGATIVE charges.

Note that all the oxygen atoms are equivalent, and we could even propose a Lewis structure of #""^(2+)S(-O^(-))_4#.....#(O=)_2S(-O^(-))_2# is a more conventional representation.