What is the limit of #1/sqrt(x^2 + 1)-x # as x goes to infinity?
1 Answer
Sep 16, 2015
Explanation:
I'm not sure the question is typed correctly, so I'll give solutions to both possibilities.
# = 0- lim_(xrarroo) x = -oo#
And
# = lim_(xrarroo) (sqrt(x^2 + 1)+x)/(x^2+1-x^2)#
# = lim_(xrarroo) (sqrt(x^2 + 1)+x)#
#= lim_(xrarroo) sqrt(x^2 + 1)+ lim_(xrarroo)x#
# = oo+oo=oo#