What is the limit of #(5x-9)/(4x^3+1)# as x goes to infinity?

2 Answers
Oct 9, 2015

0

Explanation:

It's clear from the graph shown below that as x gets bigger and bigger, the line gets closer and closer to 0. I know it's not very rigorous, but it works.

graph{(5x-9)/(4x^3+1) [-10, 10, -5, 5]}

Oct 9, 2015

See the explanation section.

Explanation:

For all #x# other than #0#, we have:

#(5x-9)/(4x^3+1) = (x^3(5/x^2-9/x^3))/(x^3(4+1/x^3))#

# = (5/x^2-9/x^3)/(4+1/x^3)#

#lim_(xrarroo) (5/x^2-9/x^3) = 0#

and
#lim_(xrarroo) (4+1/x^3) = 4#.

So,

#lim_(xrarroo) (5x-9)/(4x^3+1) = lim_(xrarroo) (5/x^2-9/x^3)/(4+1/x^3)#

# = 0/4 = 0#