# What is the limit of (8-(7y^2))/((2y^2)+9y) as x goes to infinity?

Oct 26, 2015

AS $y$ goes greater and greater, ${y}^{2}$ goes greater at a very much faster rate.

#### Explanation:

So further on, the $8$ above the bar and the $9 y$ make less and less of a difference, and the function will get nearer and nearer to
$\frac{- 7 \cancel{{y}^{2}}}{2 \cancel{{y}^{2}}} = - 3 \frac{1}{2}$

Or, in "the language":

${\lim}_{y \to \infty} \frac{8 - 7 {y}^{2}}{2 {y}^{2} + 9 y} = - 3 \frac{1}{2}$