Question

What is the limit of `(x^2-1)/(2x^2-x-1)` as x goes to infinity?

Answer 1

`1/2`

Explanation:

Since the quadratic terms dominate the function at infinity, we may write this limit as :

`lim_(x->oo)(x^2-1)/(2x^2-x-1)=lim_(x->oo)x^2/(2x^2)=1/2`