# What is the limit of x to infinity of x^2-3/e^x?

##### 1 Answer

Jun 8, 2018

#### Explanation:

We want to evaluate the limit

#L=lim_(x->oo)(x^2-3)/e^x#

Which is an indeterminate form

So we can apply **L'Hôpital's rule**

#color(blue)(lim_(x->c)f(x)/g(x)=lim_(x->c)(f'(x))/(g'(x))#

Thus

#L=lim_(x->oo)(2x)/e^x#

An indeterminate form

#L=lim_(x->oo)(2)/e^x=0#