What is the limiting reactant when 6.00 g of BaCl2 reacts with 5.00 g of Na3PO4 to form the precipitate Ba3(PO4)2?
To find out the limiting reactant, you calculate the number of moles of the reactant and the limiting reactant is the one with the least number of moles.
The reaction is;
No. of moles =
In this case,
No. of moles (
No. of moles of (
This number of moles if for 1 molecule of the reactants.
But in this case 3 molecules of
No. of moles of 3 molecules of
No. of moles of 2 molecules of
you have to balance the equation
from the ratio of reaction you see that are need 3 mol of
Then you have to calculate the mol of the reactants
You have less