# What is the limiting reagent?

Jun 17, 2017

The limiting reagent is $C O$..........

#### Explanation:

$F {e}_{2} {O}_{3} \left(s\right) + 3 C O \left(g\right) \rightarrow 2 F e \left(s\right) + 3 C {O}_{2} \left(g\right)$

And thus $\text{ferric oxide}$ reacts with THREE equiv $C O$ to give us 2 equiv iron metal, and 3 equiv of carbon dioxide.

$\text{Moles of ferric oxide} = \frac{21.00 \cdot g}{159.69 \cdot g \cdot m o {l}^{-} 1} = 0.132 \cdot m o l$

$\text{Moles of carbon monoxide} = \frac{10.50 \cdot g}{28.01 \cdot g \cdot m o {l}^{-} 1} = 0.375 \cdot m o l$

Given these molar quantities, ONLY $0.125 \cdot m o l$ $\text{ferric oxide}$ will react, given that it is the reagent in excess, and carbon monoxide is the reagent is in deficiency.