# What is the limiting reagent when 3.10 mol of SO_2 reacts with 2.75 mol of O_2 according to the equation: SO_2 + O_2 -> SO_3?

Jun 8, 2016

Your equation is incorrect; it is not stoichiometrically balanced.

#### Explanation:

Synthesis of sulfur trioxide is represented stoichiometrically:

$S {O}_{2} \left(g\right) + \frac{1}{2} {O}_{2} \left(g\right) \rightarrow S {O}_{3} \left(g\right)$

This equation tells us that $64 \cdot g$ of sulfur dioxide reacts with $16$ dioxygen gas to give $80 \cdot g$ of sulfur trioxide.

Clearly, given this equation, there is excess dioxygen gas. The given molar quantity of sulfur dioxide requires only $1.6 \cdot m o l$ dioxygen gas.

You will have to calculate the mass of product yourself.