What is the mass in grams of 5.56 X 10^22 lead atoms?

1 Answer
Jan 25, 2017

Well, 6.0221xx10^23 individual lead atoms have a mass of 207.2*g.

Explanation:

So we take the quotient,

(5.56xx10^22" atoms")/(6.022xx10^23*"atoms"*mol^-1) xx207.2*g*mol^-1 =

"How many grams?"

This idea of mass equivalence, of a mass representing a GIVEN number of atoms or molecules, is central to chemistry, and it is worth getting right. Using this concept, for a given reactant, we can predict the mass of products likely to be observed. Over your studies in chemistry, you will do many such problems.