What is the mass in grams of 67.2 L of nitrogen dioxide, NO_2?

May 22, 2017

$d = 9.47 \times {10}^{4} \text{ g}$

Explanation:

Step 1. Determine the density of nitrogen dioxide
$d = 1.45 {\text{ g"/"cm}}^{3}$

Recall that $1 \text{ cm"^3=1 " mL}$, so
d=1.45 "g"/"cm"^3=1.45 ("g")/(" mL")

Step 2. Write the mass as a function of density and volume.
"m"="d"xx"V"=(1.45 " g"/"mL")xx(67.2 " L")

Step 3. Convert L to mL
$\text{m"="d"xx"V"=(1.45 "g"/"mL")xx(67.2 " L")xx((1000" mL")/(1" L"))=97,400 "g}$

Or,
$d = 9.47 \times {10}^{4} \text{ g}$