Question

What is the mass (in grams) of 8.34 moles calcium acetate?

Answer 1

One mole of `Ca{O(O=)C-CH_3}_2` has a mass of `158.17` `g`.

Explanation:

So, if there are `8.34` mol calcium acetate, there are `8.34*cancel(mol)xx158.17*g*cancel(mol^-1)` `~=` `1300` `g`.

But please don't trust my 'rithmetic.