# What is the mass in grams of a single atom of silver?

$1.7913 \cdot {10}^{- 22} g$
$1 m o l A g = 107.87 g A g$
$6.022 \cdot {10}^{23} a t o m s A g = 107.87 g A g$
$1 a t o m A g = 1.7913 \cdot {10}^{- 22} g$