Question

What is the mass of 0.0914 moles of ammonium sulfate?

Answer 1

12.06g

Explanation:

The gram-molecular weight of any compound is the sum of the atomic weights of each element. For ammonium sulfate this is `(NH_4)_2SO_4` = 28+8+32+64 = 132 g/mol. Thus, 0.0914 moles has a mass of 0.0914 mol * 132 g/mol = 12.06g

Answer 2

The mass of `"0.0914 mol"` ammonium sulfate is `color(blue)("12.1 g")` rounded to three significant figures due to `"0.0914 mol"`.

Explanation:

In order to determine the mass of `"0.0914 mol"` ammonium sulfate, you must first know its chemical formula, which is `"(NH"_4)_2"SO"_4"`. You then use the formula to determine its molar mass. Then multiply its molar mass by its given mass. This will give the mass of `"0.0914 mol"` ammonium sulfate in grams.

Molar Mass of Ammonium Sulfate
Multiply the subscript of each element by its molar mass, which is its atomic weight on the periodic table in grams/mole.

Molar mass of `"(NH"_4)_2"SO"_4":` `(2xx14.007 color(white)(.)"g/mol N")+(8xx1.008 color(white)(.)"g/mol H")+(1xx32.06color(white)(.) "g/mol S")+(4xx15.999color(white)(.) "g/mol O")="132.134 g/mol (NH"_4)_2"SO"_4"`

Mass of Ammonium Sulfate in 0.0914 mol
Multiply the given mol ammonium sulfate by its molar mass.

`0.0914color(red)cancel(color(black)("mol"))xx(132.134"g")/(1color(red)cancel(color(black)("mol")))="12.1 g"` `("NH"_4)_2"SO"_4"`

The mass of `"0.0914 mol"` ammonium sulfate is `"12.1 g"` rounded to three significant figures due to `"0.0914 mol"`.