What is the mass of 0.0914 moles of ammonium sulfate?

2 Answers
Apr 9, 2017

Answer:

12.06g

Explanation:

The gram-molecular weight of any compound is the sum of the atomic weights of each element. For ammonium sulfate this is #(NH_4)_2SO_4# = 28+8+32+64 = 132 g/mol. Thus, 0.0914 moles has a mass of 0.0914 mol * 132 g/mol = 12.06g

Apr 10, 2017

Answer:

The mass of #"0.0914 mol"# ammonium sulfate is #color(blue)("12.1 g")# rounded to three significant figures due to #"0.0914 mol"#.

Explanation:

In order to determine the mass of #"0.0914 mol"# ammonium sulfate, you must first know its chemical formula, which is #"(NH"_4)_2"SO"_4"#. You then use the formula to determine its molar mass. Then multiply its molar mass by its given mass. This will give the mass of #"0.0914 mol"# ammonium sulfate in grams.

Molar Mass of Ammonium Sulfate
Multiply the subscript of each element by its molar mass, which is its atomic weight on the periodic table in grams/mole.

Molar mass of #"(NH"_4)_2"SO"_4":##(2xx14.007 color(white)(.)"g/mol N")+(8xx1.008 color(white)(.)"g/mol H")+(1xx32.06color(white)(.) "g/mol S")+(4xx15.999color(white)(.) "g/mol O")="132.134 g/mol (NH"_4)_2"SO"_4"#

Mass of Ammonium Sulfate in 0.0914 mol
Multiply the given mol ammonium sulfate by its molar mass.

#0.0914color(red)cancel(color(black)("mol"))xx(132.134"g")/(1color(red)cancel(color(black)("mol")))="12.1 g"##("NH"_4)_2"SO"_4"#

The mass of #"0.0914 mol"# ammonium sulfate is #"12.1 g"# rounded to three significant figures due to #"0.0914 mol"#.